DYNAMIC HOT AIR EVAPORATING SYSTEMS

My system can make use of any energy source, not only wave energy or solar power or even city grid power, and is by design highly effective, efficient and produces a product which is 100% salt free, and can likewise be used to clean any form of water with unpleasing things in it.

In short, the description is simple, air has a specific water holding capacity and this capacity increases with temperature, such that very hot air can hold up to 3 times the water as cool air, and by this function we can evaporate, and separate and move vast volumes of moisture by air flow to be cooled down with the result of that air dumping all it's excess water which can be collected and used as fresh water, literally as clean as rain water.
Figure one illustrate the basic principle of the heated air flow system (driven by wave energy), it being easily expanded in size, maintained and repaired because it has no filters or specialized parts which are expensive.

PROJECT LEADER : Luis Edwardo Correa,
818-397-1352
empiricalchurch.org
Los Angeles, California.

A longer text description is as follows...

Technical feasibility,
1) Air at 70*f can hold around one pound of water as moisture per cubic meter, while at 150*f that same one M^3 of air can hold 3 pounds.

2) To heat air, requires 1 KJ / M^3 of air per *c , therefore any 100*f shift would require 55*c x 1KJ = 55 KJ to heat each M^3 of air from 70*f to 170*f, or better a 200 *f rise in heat will require 111 KJ of energy per M^3 of air to heat it to 270*f.

3) Air will when absorbing water cool off due to the absorption of heat by water when evaporating, such that for every cu cm of water, we would need potentially up to 2000 joules of energy to evaporate (at one ATM) , such that in the worst case per liter we would need an additional 2000 j x 1000 = one liter = 2,000,000 j of energy, raising the energy needed per liter to 2,111,000 joules. And with the needed 400 liters or more per day, 400 x 2,111,000 j = 844.4 million joules per day producing 400 liters of pure 100% CLEAN water. 844 Million joules / 24 = 35.2 Million joules an hour, and divided by 60 minutes = 586,388 joules per minute, and per second is = 9773 joules per second, or put simply the basic WORST CASE ENERGY NEEDS would be 9773 watts, as the power supply from wave solar or any source to drive this desalination system, which can provide 400 liters per day of pure water.
---> HOWEVER, by super heating the air to 270 degrees *f, would only require 111 KJ per cubic meter, such that by introducing the heated air into a low pressure system being driven by a vacuum fan system at the exit port the gas will maintain at an expanding lowering pressure state while traveling over (possibly solar heated) sea water and can absorb the maximum amount of water while the air gives off the least amount of heat and the water vapor is encouraged to absorb heat on evaporation, it being needed to greatly over heat the air in order to avoid the need to heat the water, however the use of DARK BODY SOLAR HEATING seems logical to heat in inflow of water and increase evaporation rates and allow any cooled gas to further drop the pressure and prevent loses which would occur if the air was pushed under pressure through the system instead of pulled by a vacuum. In this way we should be able to avoid the need to fully heat the water as we will be running a large volume of sea water under super heated low air pressure threw the machine to allow the removal any brine and salt and prevent it's collection in the machine.
It being understood that the collection of water maybe less than maximum which may require greater heating of any air volume and the use of lower pressure, but doing that will require vastly less energy than attempting boiling at one ATM.
Also spray nozzles may be applied to spray the sea water into the air flow, allowing the water vapor to move down the line, while salts will fall and can be collected by cleaver designs. In fact this type of air system of fans, and spray nozzles in ducted tubing should work all by itself without heating but would as such will require a rather large set up and a method of cooling, while a heated air system with vacuumed air flow can be much smaller.
The benefit of this system, is that it is easily cleaned, maintained, repaired and never requires the purchase of expensive replacement filters.

4) The other power needs will be small by comparison, as energy costs for a standard fan at 100 watts, 1200 rpm used to draw air through the system, based on easily researched fan efficiencies and operational rates, it is easy to presume fan air flow is a minor energy loss. However also will be needed three water pumps to serve the system pumping water, but the total estimated energy drain should be no more than 500 watts, keeping the total energy needs in any system designed for about 400 liters a day below 2000 watts, and as such, any proposal I make this day is based on worst case energy needs and a 2000 watt system seems to be a safe estimate for total power needs as it relates to 400 liters a day.


System scalability,

Generally, the volume of water produced will be directly proportional to the volume of heated air flow and its AIR PRESSURE, pumped sea water intimacy with that heated air, and the volume and temperature of pumped sea water to provide cooling to the water collection section.




THE MAIN BENEFIT, of such a heated air system is that it can produce nearly pure water with no salf content, doing so in exactly the same way nature does it everyday.


-Luis Correa (Mosheh Eesho Muhammad)
818-397-1352
info@empiricalchurch.org